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Now,When posses top of window, has follen h. hos velocity v/ 2gh)(u hat(A)^(0)=u hat(A)^(2)+2as)thereTime taken T to J^(@) from h to h+Lw, accelerating at g is{:[L_(w)=v(2gh)t+g+ hat(A)^(2)//2quad(s=(1t+at hat(A)^(2)//2):}],[h=(uL omega hat(A)^(2)-4gL ... See the full answer