# Question Assume TCP is sending segments using a maximum window size (64 KB) on a channel that has infinite bandwidth and an average roundtrip time of 20 ms.  (a) What is the maximum throughput?  (b) How does the throughput change if the roundtrip time increases to 40 ms?

KENXAE The Asker · Computer Science

Assume TCP is sending segments using a maximum window size (64 KB) on a channel that has infinite bandwidth and an average roundtrip time of 20 ms.

(a) What is the maximum throughput?

(b) How does the throughput change if the roundtrip time increases to 40 ms?

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&#12304;General guidance&#12305;The answer provided below has been developed in a clear step by step manner.Step1/3Hello,the formula for calculating the maximum throughput is = maximum window size/ Round trip timeExplanation:Please refer to solution in this step.Step2/3Here, in our question the maximum window size is given to be = 64 KBa)the average round trip time = 20 ms.Maximum throughput(when round triptime = 20) = \begin{align*} \mathrm{{M}{a}\xi\mu{m}{t}{h}{r}{o}{u}{g}{h}{p}{u}{t}{\left({w}{h}{e}{n}{r}{o}{u}{n}{d}{t}{r}{i}{p}{t}{i}{m}{e}={20}\right)}} &= \mathrm{\frac{{\max{i}{m}{u}{m}{w}{i}{n}{d}{o}{w}{s}{i}{z}{e}}}{{{r}{o}{u}{n}{d}{t}{r}{i}{p}{t}{i}{m}{e}}}} \end{align*}\( \begin{align*} \mathrm{{t}{h}{r}{o}{u}{g}{h}{p} ... See the full answer