See Answer

Add Answer +20 Points

Community Answer

See all the answers with 1 Unlock

Get 4 Free Unlocks by registration

Get 4 Free Unlocks by registration

1) Given mass of the baseball  = 0.15 kg Suppose incoming speed of baseball = v Thus momentum of baseball before collision = Mass*Velocity = 0.15v Mass of milk bottle = 2.4 kg Initial speed of milk bottle = 0 thus momentum of milk bottle before collision = 0 Hence, total momentum of the system before collision = 0.15v Now after collision, baseball bounces back with a speed of 0.1v.  Thus momentum of baseball = 0.15*(-0.1v) = -0.015v Suppose momentum of milk bottle = p total momentum of system after collision = -0.015v + p From conservation of momentum, we know that total momentum of system before collision = total momentum of system after collision Thus, 0.15v = -0.015v + p Hence, p = 0.165v Thus, speed of milk bottle after collision = momentum/ mass = 0.165v/ 2.4 = 0.0688v Thus, (vbottle)f / (vbaseball)i  = 0.0688 = 6.88% 2) Mass of turn table = 2.5 kg Diameter of the turn table = 20 cm = 0.2 m Thus, radius of th ... See the full answer