At what speed the mass of an object will be 2.25 times its rest mass?*

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using Relativity principlem \begin{array}{rlrl}m_{0} & m_{0} & =\text { Rest mass } \\\sqrt{1-\frac{v^{2}}{c^{2}}} & m & =\text { Relativstic mass } \\v & =\text { speed of mass } \\c & =\text { speed of light } \\& =3 \times 10^{8} \mathrm{~m} / \mathrm{s}\end{array}given m=2.25 m_{0}\begin{array}{l}\Rightarrow \sqrt{1-\frac{v^{2}}{c^{2}}}=\frac{1}{2.25} \\\Rightarrow \quad 1-\frac{v^{2}}{c^{2}}=\left(\frac{1}{2.25}\right)^{2}=\frac{16}{81} \\\Rightarrow \quad \frac{v^{2}}{c^{2}}=1-\frac{16}{81}=\frac{65}{81} \\V=\sqrt{\frac{65}{81}} \mathrm{C} \\V=2.6874 \times 10^{8} \mathrm{~m} / \mathrm{s} \\=268741924 \mathrm{~ms} \\\end{array} ...