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Answer -Given rarr A rigid wire loop length L and width w is placed in a magnetic field B hat(ȷ).The current in loop is I in clockwise direction.Now, the to magnetic field vec(B) and current in loop I. there's a magnetic force F_(m) acting on loop.The expression for magnetic force F_(m) is given by -F_(m)=int I( vec(dl)xx vec(B))Tie. direction of magnetic force vec(F_(m)) is along ( vec(dl)xx vec(B)) vector Here, I = curent dl= length Element VectorB= magnetic fieldNow, for A_(1)B_(1):(F_(m))_(A_(1)B_(1))=int I( bar(dl)xx bar(B))=I int dl hat(ȷ)xx B hat(ȷ)(F_(m))_(A_(1)B_(1))=I*B*L_(A_(1)B_(1))( hat(ȷ)xx hat(ȷ))=0{ because hat(ȷ)xx hat(j)=0}Similarly for C_(1)D_(1):(F_(m))_(C_(1)D_(1))=int I( vec(dl)xx vec(B)){:[=int I*dl(- hat(ȷ))xx B hat(ȷ)],[=I*B*L_(G_(C)D_(1))(- hat(ȷ)xx hat(ȷ))],[=0{- hat(ȷ)xx hat(ȷ)=0}]:}for length{:[B_(1)G_(1):(F_(m))_(B_(1)G)=I int vec(dl) ... See the full answer