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\begin{array}{l}x 1+x 2=248 \\x 4+x 5=248 \\x 1-x 3-x 4=0 \\x 2+x 3-x 5=0\end{array}The augmented matrix is\mathrm{R} 3=\mathrm{R} 3-1 * \mathrm{R} 11-00\begin{array}{cc}0 & 248 \\1 & 248 \\0 & -248 \\-1 & 0\end{array}interchange R 2 and R 3\begin{array}{ll}1 & 1 \\ 0 & -1 \\ 0 & 0 \\ 0 & 1\end{array}\begin{array}{cc}0 & 0 \\ -1 & \\ 0 & \\ 1 & \end{array}\begin{array}{cc}0 & 0 \\ -1 & 0 \\ 1 & 1 \\ 0 & -1\end{array}\begin{array}{cc}0 & 248 \\ 0 & -248 \\ 1 & 248 \\ -1 & 0\end{array}\mathrm{R} 2=-1 * R 21000\begin{array}{ll}1 & 0 \\ 1 & 1 \\ 0 & 0 \\ 1 & 1\end{array}\begin{array}{ll}0 & 0 \\ 1 & 1 \\ 0 & 1 \\ 1 & 0\end{array}R 1=R 1-1^{*} R 2, R 4=R 4-1^{*} R 2R 1=R 1+1 * R 3, R 2=R 2-1 * R 3, R 4=R 4+1 * R 3\begin{array}{cccccc}1 & 0 & -1 & 0 & 1 & 248 \\0 & 1 & 1 & 0 & -1 & 0 \\0 & 0 & 0 & 1 & 1 & 248 \\0 & 0 & 0 & 0 & 0 & 0\end{array}It is reduced row echelon form of matrixHence1 \times 1-1 \times 3+1 \times 5=2481 \times 2+1 \times 3-1 \times 5=01 \times 4+1 \times 5=248Hencex 1=248+1 \times 3-1 \times 5\times 2=0-1 \times 3+1 \times 5x 4=248-1 \times 5We choose x 3=0 and x 5=0x 1=248x 2=0x 4=248hence\begin{aligned}\text { total time } & =2^{*} 248+2^{*} 2^{*} 248 \\& =1488 \text { minutes answer }\end{aligned}Please positively rate the solution. Thanks. ...