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6.54 KN Taking Moment about B=0\begin{array}{c}R_{A} \sin 82^{\circ} \times(4.4+4.4)-m g(4.4) \sin 45^{\circ}-T(4.4) \cos 45^{\circ}=0 \\R_{A} \sin 82^{\circ} \times 8.8-m \times 9.81(4.4) \sin 45-T(4.4) \cos 45^{\circ}=6 \\15 \sqrt{2} \times 0.99 \times 8.8-m \times 9.81 \times 4.4 \frac{1}{\sqrt{2}}-5.5 .4 \frac{1}{\sqrt{2}}=0 \\261.36-m 43.164-66=0 \\43.164 m=282.36 \\\therefore m=6.54 \mathrm{kN}\end{array} ...