Question (b) Suppose the object in Figure 1 is part of a spherical shell. It can be described by asr 36,60º < 0< 90°, 60° < $ 900where the surface ø= 45° is ABCD, the surface r= a the same as AEHD, and surface 8 = 60° is AEFB, and. If the surface areas of AEHD and ABCD are given as 1.216 m2 and 4.189 m², respectively, determine the values of q and b. - B F rde А) E G dr DH Figure 1

T3IZ26 The Asker · Electrical Engineering



Transcribed Image Text: (b) Suppose the object in Figure 1 is part of a spherical shell. It can be described by asr 36,60º < 0< 90°, 60° < $ 900where the surface ø= 45° is ABCD, the surface r= a the same as AEHD, and surface 8 = 60° is AEFB, and. If the surface areas of AEHD and ABCD are given as 1.216 m2 and 4.189 m², respectively, determine the values of q and b. - B F rde А) E G dr DH Figure 1
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Transcribed Image Text: (b) Suppose the object in Figure 1 is part of a spherical shell. It can be described by asr 36,60º < 0< 90°, 60° < $ 900where the surface ø= 45° is ABCD, the surface r= a the same as AEHD, and surface 8 = 60° is AEFB, and. If the surface areas of AEHD and ABCD are given as 1.216 m2 and 4.189 m², respectively, determine the values of q and b. - B F rde А) E G dr DH Figure 1
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1Information given{:[a <= gamma <= b],[60^(@) <= theta <= 90^(@)],[60^(@) <= phi <= 90^(@)]:}surface ABCD=>phi=45^(@)surface AEHD=>r=asurface AEFB=>theta=60^(@)area of surface AEHD=1.216m^(2)area of surface ABCD=4.189m^(2)we have to find values of a &amp; br=a for surface AEHD2{:[" and ares of snrtace "AEHD=1.216m^(2)],[" i.e "quad∬d vec(s)* hat(a)=1.216m^(2)],[" so "],[∬d vec(phi)* hat(phi)_(gamma)=int_(phi=60^(@))^(phi=9=60^(@))int_(theta=90)^(theta=90)gamma^(2)sin theta d theta d phiquad{gamma=a}],[1.216=a^(2)int_(theta=60)^(90^(@))sin theta d thetaint_(phi=60^(@))^(90^(@))d phi],[1.216=a^(2)(-cos theta)|_(theta=60^(@))^(theta=90^(@))phi|_(phi=60^(@))^(90^(@))],[1.216=a^(2)(-cos 90^(@)-(-cos 60^(@)))(90^(@)-60^(@))],[1.216=a^(2)(0+0.5)((pi)/(2)-(pi)/(3))],[1.216=a^(2)xx0.5 xx(pi)/(6)quad{[90^(@)=pi//2 ... See the full answer