Question Solved1 Answer Beam with 4 mm thick thin-walled cross-section shown in Fig. 1, is subjected to a vertical shear of 200 kN. Draw the shear flow and force diagram Locate the shear centre of the cross-section with respect to the centre of the web Find the shearing stress at the junctions of flanges and webs Draw the shear stress distribution across the cross-section Why finding shear centre is important? 100 mm 400 mm 100 mm 100 mm 4 mm 200 mm 100 mm 100 mm Figure 1 (all dimensions are between centre lines)
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Transcribed Image Text: Beam with 4 mm thick thin-walled cross-section shown in Fig. 1, is subjected to a vertical shear of 200 kN. Draw the shear flow and force diagram Locate the shear centre of the cross-section with respect to the centre of the web Find the shearing stress at the junctions of flanges and webs Draw the shear stress distribution across the cross-section Why finding shear centre is important? 100 mm 400 mm 100 mm 100 mm 4 mm 200 mm 100 mm 100 mm Figure 1 (all dimensions are between centre lines)
More Transcribed Image Text: Beam with 4 mm thick thin-walled cross-section shown in Fig. 1, is subjected to a vertical shear of 200 kN. Draw the shear flow and force diagram Locate the shear centre of the cross-section with respect to the centre of the web Find the shearing stress at the junctions of flanges and webs Draw the shear stress distribution across the cross-section Why finding shear centre is important? 100 mm 400 mm 100 mm 100 mm 4 mm 200 mm 100 mm 100 mm Figure 1 (all dimensions are between centre lines)
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  Answer: -Given dala,Vertical shear force, v=200krShear stres T=(VA bar(4))/( bar(Tb))Shear How, b=1tau=(VA( bar(y)))/(I)rarr" Gineral Eqn of shearffow "Drawing of shear thowThis is Symetrical strecture.Shear stres at the Junction of flanges 4 webs.{:[ bar(y)=(2+100+(200)/(2))],[=(2+100+100)],[ bar(y)=202mm],[sum_(xx)=[((1)/(12)xx4xx100^(3))xx2]+[(1)/(12)xx500 xx4^(3)]+],[I_(xx)=2.3340 xx10^(7)mm4],[b=(100-:400+4xx4xx400^(3)]+[(1 ... See the full answer