Calculate the pH of a solution obtained by mixing 165.05 mL of 0.22 M CH3COOH with 165.05 mL of 0.22 NaOH.
Ka (CH3COOH)= 1.8×10−5
" Mmol of "{:[CH_(3)COOH=0.22 xx165.05],[=36.311mmol]:}" mmrr of "NaOH=0.22 xx165.05=36.311mmolso, it is Eqvivalent poi ... See the full answer