Question can anyone solve this three qestions plz ? LALALISLS m EXERCISES 9.3 > In problems 1-4, match each graph to equations A-D. A. 목 B. C. V VP D. 1. 2. 3. *** In Exercises 5-12, find the standard form of the equation of each hyperbola satisfying the given conditions. 5. Foci:(0, -3),(0,3); vertices: (0, -1),(0,1) 6. Foci: (0,–6),(0,6); vertices: (0,-2),(0,2) 7. Foci:(-4,0).(4,0); vertices: (-3,0),(3,0)

A. \frac{x^{2}}{4}-\frac{y^{2}}{1}=1 \Rightarrow \frac{x^{2}}{2^{2}}-\frac{y^{2}}{1^{2}}=1   So, it is in the form of \Rightarrow \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1   So, the transverse axis is horizontal ----(1)   Vertices are (-a,0) and (a,0) = (-2,0) and (2,0) -----(2)   The graph that satisfies (1) and (2) is GRAPH 3 ----Ans.     B. \frac{x^{2}}{1}-\frac{y^{2}}{4}=1 \Rightarrow \frac{x^{2}}{1^{2}}-\frac{y^{2}}{2^{2}}=1   So, it is in the form of \Rightarrow \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1   So, the transverse axis is horizontal ----(1)   Vertices are (-a,0) and (a,0) = (-1,0) and (1,0) -----(2)   The graph that satisfies (1) and (2) is GRAPH 4 ----Ans.     C. y^{2}-\frac{x^{2}}{4}=1 \Rightarrow \frac{y^{2}}{1^{2}}-\frac{x^{2}}{2^{2}}=1   So, it is in the form of \Rightarrow \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1   So, the transverse axis is vertical ----(1)   Vertices are (0,-a) and (0,a) = (0,-1) and (0,1) -----(2)   The graph that satisfies (1) and (2) is GRAPH 2 ----Ans.     D. \frac{y^{2}}{4}-x^{2}=1 \Rightarrow \frac{y^{2}}{2^{2}}-\frac{x^{2}}{1^{2}}=1   So, it is in the form of \Rightarrow \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1   So, the transverse axis is vertical ----(1)   Vertices are (0,-a) and (0,a) = (0,-2) and (0,2) -----(2)   The graph that satisfies (1) and (2) is GRAPH 1 ----Ans.     5.) Foci: (0,-3), (0,3) and vertices: (0,-1), (0,1)   The traverse axis is vertical ----(1)   a = 1 and c = 3 => a2 = 1 and c2 = 9 -----(2) b2 = c2 - a2 => b2 = 9 - 1 => b2 = 8 -------(3)   The equation is \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1 \Rightarrow \frac{y^{2}}{1}-\frac{x^{2}}{8}=1   -----Ans.     6.) Foci: (0,-6), (0,6) and vertices: (0,-2), (0,2)   The traverse axis is vertical ----(1)   a = 2 and c = 6 => a2 = 4 and c2 = 36 -----(2) b2 = c2 - a2 => b2 = 36 - 4 => b2 = 32   -------(3)   The equation is \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1 \Rightarrow \frac{y^{2}}{4}-\frac{x^{2}}{32}=1   -----Ans.     7.) Foci: (-4,0), (4,0) and vertices: (-3,0), (3,0)   The traverse axis is horizontal ----(1)   a = 3 and c = 4 => a2 = 9 and c2 = 16 -----(2) b2 = c2 - a2 => b2 = 16 - 9 => b2 = 7 -------(3)   The equation is \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 \Rightarrow \frac{x^{2}}{9}-\frac{y^{2}}{7}=1     -----Ans.                         ...