Community Answer

Honor CodeSolved 1 Answer

See More Answers for FREE

Enhance your learning with StudyX

Receive support from our dedicated community users and experts

See up to 20 answers per week for free

Experience reliable customer service

Get Started

Let A=\left[\begin{array}{cc}1.6 & -1 \\-1.666666667 & 4\end{array}\right]Put |A-k I|=0\left|\begin{array}{cc}1.6-k & -0.75 \\-1.666666667 & 3.6-k\end{array}\right|=0k^{\wedge} 2-5.2 k+4.51=0\mathrm{k}=1.1,4.1smaller eigenvalue =1.1 \quad answerlarger eigenvalue =4.1 \quad answer\Rightarrow \quad solution isx(t)=4.9167 e^{\wedge}(1.1 t)+0.0833 e^{\wedge}(4.1 t) answery(t)=3.2778 e^{\wedge}(1.1 t)-0.2778 e^{\wedge}(4.1 t) \quad answer\Rightarrow \quad solution isx(t)=4.9167 e^{\wedge}(1.1 t)+0.0833 e^{\wedge}(4.1 t) answery(t)=3.2778 e^{\wedge}(1.1 t)-0.2778 e^{\wedge}(4.1 t) \quad answeroprion A is correct All the solution curve would run away from 0 .In case of further clarification needed, please write below in the comment section. Please positively rate the solution. Thanks. ...