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\begin{array}{l}K_{\mathrm{a}}=8.4 \times 10^{-4} \\\qquad \Rightarrow K_{\mathrm{a}}=-\log K_{\mathrm{a}}=-\log \left(8.4 \times 10^{-4}\right)=3.08\end{array}Buffer whose \mathrm{pH} value equal to its \mathrm{p} K_{\mathrm{a}} is considered as the best buffer and will have the maximum buffer capacity.Since the \mathrm{p} K_{\mathrm{a}} of acid is closer to the \mathrm{pH} of the buffer 3, \mathrm{pH}=3 is the most effective choice. ...