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(3)(a) bar(AD)+ bar(DH)By Triongular's law bar(AB)+ bar(BC)= bar(AC)so, bar(AD)+ bar(DH)=A bar(AH)(b){:[ bar(AB)+ bar(BF)+ bar(FG)],[= bar(AF)+ bar(FG)],[= bar(AG)]:}(c) bar(AE)+ bar(HC)From the diageam, bar(AE)= bar(DH){:[ bar(AE)+ bar(H ... See the full answer