P2

Community Answer

Step 1Given: L=470mH=0.47HC=0.112 muF=0.112 xx10^(-6)FSolution: omega_(0)=(1)/(sqrt(LC)){:[omega_(0)=(1)/(sqrt((0.47)(0.112 xx10^(-6))))=4359rad//s],[w_(0)=4.359krad//s" Ans. "]:}Step 2(b) omega_(d)=sqrt((1)/(LC)-((R)/(2L))^(2)){:[omega_(d)=sqrt((1)/((0.47)(0.112 xx10^(-6)))-[( ... See the full answer