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\frac{d y}{d x}=x^{2}(y-1)for \operatorname{all} y \wedge x=0for all x at y=1\frac{d y}{d x}=0domain [-3,3]Range [-3,3]Ascopes in3^{\text {nd }} and 4^{\text {th }} quadrant are negative except y=1B \therefore All points that has negative slofe are (1,-1)(1,-2)(1,-3)\begin{array}{l}(1,-1)(1,-2)(1,-3) \\(3,-1)(3,-2)(2,-3) \\(3,-2)(3,-3)\end{array} ...