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1. Ans:-Apply total mass balonce,\frac{\delta_{1} q_{1}=-\frac{\varnothing}{g_{2}}=\frac{d}{d t}\left(\varnothing v_{1}\right)}{q_{1}-q_{2}}=\frac{d}{d t}-(1) \quad\left\{h_{1}=A \cdot h\right\}For \tan k 2,\begin{aligned}\rho_{32}-9 q_{3} & =\frac{d}{d t}\left(\rho v_{2}\right) \\9_{2}-3_{3} & =\frac{A_{2} d h_{2}}{d t_{2}} \\a_{3}(t) & =\frac{h_{2}(t)}{R_{2}}\end{aligned}2. \mathrm{Eg}^{n}(1),(2),(3) &(4) are simulternedus eyn and on solving, we get.where,\tau_{p_{1}}=A_{1} R_{1} \longrightarrow \tau_{p_{2}}=42 R_{2}Given:- A_{1}=1 \mathrm{~m}^{2}, A_{2}=0.5 \mathrm{~m}^{2}\begin{array}{l}R_{1}=0.5 \mathrm{hm}^{-2}, R_{2}=2.0 \mathrm{hm}^{-2} \\\tau_{P_{1}}=A_{1} R_{1}=1 \times 0.5=0.5 \mathrm{hr} \quad \tau_{P_{2}}=0.5 \times 2.0= \\\theta_{p}(s)=\overline{H I C Q} \leq \quad \tau_{p_{2}}=1 \\\end{array}G_{p}(s)=\frac{\bar{H}_{2}(s)}{\bar{q}_{1}^{\prime}(0)}=\frac{2}{(0.5)(1) s^{2}+(0.5+1+(1)(2.0)) s+1}G p(s)=\frac{2}{0.5 s^{2}+3.5 s+1}Ans ...