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Step 1Given: n = 10b_{1}=0.3943S_{b 1}=0.0178  Step 2Solution:a) The hypothesis test:H_{o}: \beta_{1}=0H a: \beta_{1} \neq 0The option E is correct answer.Test statistic t :t=\frac{b_{1}-\beta_{1}}{S_{b 1}}t=\frac{0.3943-0}{0.0178}t = 22.15Critical value:At α = 0.05 significance leveldf = n-2 = 10 - 2 = 8t critical = t (\frac{\alpha}{2},df) = t(0.025, 8)t critical = 2.3060Rejection rule:Reject Ho, if t > t critical (2.31)Or if t < - t critical (2.31)Otherwise do not reject.Since, test statistic t(22.15) > t critical (2.31)Reject Ho. There is sufficient evidence to conclude that there is a linear relationship between temperature and ice cream sales.Step 3b) The 95% confidence interval:CI = b1 ± t critical * sb1CI = 0.3943 ± 2.3060*0.0178CI = 0.3943 ± 0.0410CI = (0.3533, 0.4353)The​ 95% confidence interval is0.353 ≤ β1 ≤ 0.435 ...