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Step 1 Solution:-∑Fx=0---(Rightward positive and Leftward negative)45NA-15 = 0NA=18.75 kN∑M@B= 0----(Clockwise positive and anticlockwise negative)(W*1.2cos20 )+(1.5*1.2sin 20) -(35NA*2.4cos 20) -(45NA*2.4sin 20=0W=28.0 kNThe weight can only be found when tension T is equal to 15kN.If more heavy bar is applied it may break.  Step 2 Solution:-m=Wg=28*1039.81 =2850kgStep 3 Answer:- Answer:-m = 2850kg ...