Community Answer

Honor CodeSolved 1 Answer

See More Answers for FREE

Enhance your learning with StudyX

Receive support from our dedicated community users and experts

See up to 20 answers per week for free

Experience reliable customer service

Get Started

Convider beam BC:-+5 \sum M_{e}=0:-\begin{array}{l}\left(R_{B} \times 12\right)-\left[\left(\frac{1}{2} \times 12 \times 400\right) \times\left(\frac{2}{3} \times 12\right)\right]=0 \\R_{B}=1600 \mathrm{kN} \\R_{C}=800 \mathrm{kN}=0-R_{C}-\left(\frac{1}{2} \times 12 \times 400\right)+1600=0 \\R_{C}=80\end{array}\Sigma M_{A}=0 :-\begin{array}{l}\left(R_{2} \times 16\right)-(1600 \times 16) \\-(800 \times 4)-(1600 \times 3)=0 \\R_{2}=2100 \mathrm{kN}\end{array}+\uparrow \sum f y=0^{\prime}-\begin{array}{l}R_{1}-1600-800-1600+R_{2}=0 \\R_{1}=1600+800+1600-2100 \\R_{1}=4900 \mathrm{kN} \\R_{1}=1900 \mathrm{kN}\end{array} ...