Solved 1 Answer
See More Answers for FREE
Enhance your learning with StudyX
Receive support from our dedicated community users and experts
See up to 20 answers per week for free
Experience reliable customer service
Convider beam BC:-+5 \sum M_{e}=0:-\begin{array}{l}\left(R_{B} \times 12\right)-\left[\left(\frac{1}{2} \times 12 \times 400\right) \times\left(\frac{2}{3} \times 12\right)\right]=0 \\R_{B}=1600 \mathrm{kN} \\R_{C}=800 \mathrm{kN}=0-R_{C}-\left(\frac{1}{2} \times 12 \times 400\right)+1600=0 \\R_{C}=80\end{array}\Sigma M_{A}=0 :-\begin{array}{l}\left(R_{2} \times 16\right)-(1600 \times 16) \\-(800 \times 4)-(1600 \times 3)=0 \\R_{2}=2100 \mathrm{kN}\end{array}+\uparrow \sum f y=0^{\prime}-\begin{array}{l}R_{1}-1600-800-1600+R_{2}=0 \\R_{1}=1600+800+1600-2100 \\R_{1}=4900 \mathrm{kN} \\R_{1}=1900 \mathrm{kN}\end{array} ...