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dr Let A be the area of a circle with radius r. If dt = 4, find dA dt when r = 4.

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A=\pi r^{2}given \frac{d r}{d t}=4 and r=4\begin{array}{l}\Rightarrow \frac{d A}{d t}=2 \pi r \frac{d r}{d t} \quad \text { (Bifferentiate w.r.t t) } \\\Rightarrow \frac{d A}{d t}=2 \pi \times 4 \times 4=32 \pi \\\Rightarrow \frac{d A}{d t}=32 \pi \text { Ans }\end{array} ...

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