B)
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for question B system Ax=b is\left(\begin{array}{ccccc}1 & 2 & -1 & 1 & 1 \\ -1 & -2 & 2 & 0 & 1 \\ -1 & -2 & 3 & 1 & 3\end{array}\right)\left(\begin{array}{l}x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5}\end{array}\right)=0augmented matrix is12-111-1-2201-1-2313convert intoReduced Row Eschelon Form...Add (1 * row1) to row212-11100112-1-2313Add (1 * row1) to row312-1110011200224Add (-2 * row2) to row312-1110011200000Add (1 * row2) to row1120230011200000reduced system is\left(\begin{array}{lllll}1 & 2 & 0 & 2 & 3 \\ 0 & 0 & 1 & 1 & 2 \\ 0 & 0 & 0 & 0 & 0\end{array}\right)\left(\begin{array}{l}x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5}\end{array}\right)=0x_{1}+2 x_{2}+2 x_{4}+3 x_{5}=0 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots x_{1}=-2 x_{2}-2 x_{4}-3 x_{5}x_{2}=x_{2}......................freex_{3}+x_{4}+2 x_{5}=0 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots x_{3}=-x_{4}-2 x_{5}x_{4}=x_{4}......................freex_{5}=x_{5}.......................free.general solution is.\left(\begin{array}{l}x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5}\end{array}\right)=x_{2}\left(\begin{array}{c}-2 \\ 1 \\ 0 \\ 0 \\ 0\end{array}\right)+x_{4}\left(\begin{array}{c}-2 \\ 0 \\ -1 \\ 1 \\ 0\end{array}\right)+x_{5}\left(\begin{array}{c}-3 \\ 0 \\ -2 \\ 0 \\ 1\end{array}\right) ...