B)

Community Answer

Honor CodeSolved 1 Answer

See More Answers for FREE

Enhance your learning with StudyX

Receive support from our dedicated community users and experts

See up to 20 answers per week for free

Experience reliable customer service

Get Started

for question B system Ax=b is\left(\begin{array}{ccccc}1 & 2 & -1 & 1 & 1 \\ -1 & -2 & 2 & 0 & 1 \\ -1 & -2 & 3 & 1 & 3\end{array}\right)\left(\begin{array}{l}x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5}\end{array}\right)=0augmented matrix is12-111-1-2201-1-2313convert intoReduced Row Eschelon Form...Add (1 * row1) to row212-11100112-1-2313Add (1 * row1) to row312-1110011200224Add (-2 * row2) to row312-1110011200000Add (1 * row2) to row1120230011200000reduced system is\left(\begin{array}{lllll}1 & 2 & 0 & 2 & 3 \\ 0 & 0 & 1 & 1 & 2 \\ 0 & 0 & 0 & 0 & 0\end{array}\right)\left(\begin{array}{l}x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5}\end{array}\right)=0x_{1}+2 x_{2}+2 x_{4}+3 x_{5}=0 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots x_{1}=-2 x_{2}-2 x_{4}-3 x_{5}x_{2}=x_{2}......................freex_{3}+x_{4}+2 x_{5}=0 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots x_{3}=-x_{4}-2 x_{5}x_{4}=x_{4}......................freex_{5}=x_{5}.......................free.general solution is.\left(\begin{array}{l}x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5}\end{array}\right)=x_{2}\left(\begin{array}{c}-2 \\ 1 \\ 0 \\ 0 \\ 0\end{array}\right)+x_{4}\left(\begin{array}{c}-2 \\ 0 \\ -1 \\ 1 \\ 0\end{array}\right)+x_{5}\left(\begin{array}{c}-3 \\ 0 \\ -2 \\ 0 \\ 1\end{array}\right) ...