Question the awnser is not 1.25×10^7!! what is the awnser of part c hint:its not 1.25×10^7 Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} / \) figure shows a spherical nonconducting shell carrying a net positive rge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner 'us \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, ure 1) Part C - Find the magnitude of the electric field at radial distance \( r=12 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} \), Part A - Find the magnitude of the electric field at radial distance \( r=1 \mathrm{~cm} \), The figure shows a spherical nonconducting shell carrying a net positive charge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner radius \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, (Figure 1) Figure Part B - Find the magnitude of the electric field at radial distance \( r=5 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \). Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \). The figure shows a spherical nonconducting shell carrying a net positive charge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner radius \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, (Figure 1) Figure 1 of 1 Part C - Find the magnitude of the electric field at radial distance \( r=12 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \).
MKQRV7 The Asker · Physics
the awnser is not 1.25×10^7!!
what is the awnser of part c
hint:its not 1.25×10^7
Transcribed Image Text: Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} / \) figure shows a spherical nonconducting shell carrying a net positive rge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner 'us \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, ure 1) Part C - Find the magnitude of the electric field at radial distance \( r=12 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} \),
Part A - Find the magnitude of the electric field at radial distance \( r=1 \mathrm{~cm} \), The figure shows a spherical nonconducting shell carrying a net positive charge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner radius \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, (Figure 1) Figure Part B - Find the magnitude of the electric field at radial distance \( r=5 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \).
Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \). The figure shows a spherical nonconducting shell carrying a net positive charge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner radius \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, (Figure 1) Figure 1 of 1 Part C - Find the magnitude of the electric field at radial distance \( r=12 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \).
More Transcribed Image Text: Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} / \) figure shows a spherical nonconducting shell carrying a net positive rge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner 'us \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, ure 1) Part C - Find the magnitude of the electric field at radial distance \( r=12 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} \),
Part A - Find the magnitude of the electric field at radial distance \( r=1 \mathrm{~cm} \), The figure shows a spherical nonconducting shell carrying a net positive charge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner radius \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, (Figure 1) Figure Part B - Find the magnitude of the electric field at radial distance \( r=5 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \).
Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \). The figure shows a spherical nonconducting shell carrying a net positive charge \( 20 \mu \mathrm{C} \) uniformly distributed through its volume. It has an inner radius \( a=4 \mathrm{~cm} \) and outher radius \( b=6.5 \mathrm{~cm} \). Using Gauss' law, (Figure 1) Figure 1 of 1 Part C - Find the magnitude of the electric field at radial distance \( r=12 \mathrm{~cm} \) Express your answer numerically, to two significant figures, using \( \epsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} /\left(\mathrm{N} \cdot \mathrm{m}^{2}\right) \).
Community Answer
IVDIXN
【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/4Explanation:Guass law states that the total electric flux emerging out from a closed surface is equal to the product of sum of all enclosed charges by this surface and the constant \( \mathrm{\frac{{1}}{\epsilon}} \)given,charge in shell is 20ucouter radius = 6.5cminner radius = 4cmExplanation:Please refer to solution in this step.Step2/4Explanation:foe part A there is no enclosed charge so electric field intensity will be zeroby applying gauss law the electric field at r= 1cm will be zeroExplanation:Please refer to solution in this step.Step3/4Explanation:for part B r = 5cm is between inner radius and outer radiusby applying gauss law \( \ ... See the full answer