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F_(F_(2))^(F_(3))_(53)^(45^(@))F_(1)F_(1)=625NF_(2)=840NF_(3)=0580Nvec(F)_(1)=625(sin(53) hat(i)-cos(53) hat(ȷ))=499.147 hat(i)-376.134 hat(ȷ)vec(F_(2))=840(-sin(50) hat(i)-cos(50) hat(j))=-643.477 hat(i)-539.94 hat(j)vec(F)_(3)=580(-s ... See the full answer