Question Solved1 Answer F3 45° F1 F2 Given that F1 = 625 N, F2 = 840 N, F3 = 580 N and a = 50° determine the magnitude of the resultant force and its direction, measured counterclockwise from the positive x axis. The magnitude of the resultant force is ( round to one decimal place) : N Direction counterclockwise from positive x-axis is ( round to one decimal place) : degrees

0A76F7 The Asker · Mechanical Engineering

Transcribed Image Text: F3 45° F1 F2 Given that F1 = 625 N, F2 = 840 N, F3 = 580 N and a = 50° determine the magnitude of the resultant force and its direction, measured counterclockwise from the positive x axis. The magnitude of the resultant force is ( round to one decimal place) : N Direction counterclockwise from positive x-axis is ( round to one decimal place) : degrees
More
Transcribed Image Text: F3 45° F1 F2 Given that F1 = 625 N, F2 = 840 N, F3 = 580 N and a = 50° determine the magnitude of the resultant force and its direction, measured counterclockwise from the positive x axis. The magnitude of the resultant force is ( round to one decimal place) : N Direction counterclockwise from positive x-axis is ( round to one decimal place) : degrees
See Answer
Add Answer +20 Points
Community Answer
U9XJPK The First Answerer
See all the answers with 1 Unlock
Get 4 Free Unlocks by registration

F_(F_(2))^(F_(3))_(53)^(45^(@))F_(1)F_(1)=625NF_(2)=840NF_(3)=0580Nvec(F)_(1)=625(sin(53) hat(i)-cos(53) hat(ȷ))=499.147 hat(i)-376.134 hat(ȷ)vec(F_(2))=840(-sin(50) hat(i)-cos(50) hat(j))=-643.477 hat(i)-539.94 hat(j)vec(F)_(3)=580(-s ... See the full answer