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【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/2Solution Given the AC Circuit to find the transfer function So the inductive reactance in the s-domain will be \( \begin{align*} \mathrm{{X}_{{L}}} &= \mathrm{{s}{L}={s}}\\[3pt]\mathrm{{Z}_{{2}}} &= \mathrm{\frac{{{1}{\left({1}+{s}\right)}}}{{{1}+{1}+{s}}}=\frac{{{1}+{s}}}{{{2}+{s}}}} \end{align*} \)Explanation:Please refer to solution in this step.Step2/2So by the Voltage dividing rule the VL will be \( \begin{align*} \mathrm{{V}_{{L}}{\left({s}\right)}} &= \mathrm{\frac{{Z}_{{2}}}{{{Z}_{{2}}+{s}}}×\frac{{s}}{{{1}+{s}}}×{V}{\left({s}\right)}}\\[3pt]\mathrm{\fr ... See the full answer