Question Solved1 Answer Please write legibly and explain everything. Find the area of the region, pictured below, bounded by the curves f(x) = x - x2 - 4x – 1 and g(x) = x2 – 3x – 3 over the interval [-1,2] Enter an exact answer. This region is depicted in the following figure. Y 4 3 2 2 1 C -6 -5 -4 -3 -2 -1 2. 3 4 5 6 7 1 3 5 7
6I5OSH The Asker · Calculus
Please write legibly and explain everything.
Transcribed Image Text: Find the area of the region, pictured below, bounded by the curves f(x) = x - x2 - 4x – 1 and g(x) = x2 – 3x – 3 over the interval [-1,2] Enter an exact answer. This region is depicted in the following figure.
Y 4 3 2 2 1 C -6 -5 -4 -3 -2 -1 2. 3 4 5 6 7 1 3 5 7
More Transcribed Image Text: Find the area of the region, pictured below, bounded by the curves f(x) = x - x2 - 4x – 1 and g(x) = x2 – 3x – 3 over the interval [-1,2] Enter an exact answer. This region is depicted in the following figure.
Y 4 3 2 2 1 C -6 -5 -4 -3 -2 -1 2. 3 4 5 6 7 1 3 5 7
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We have to find Preea of Region bounded by the curves f(x)=x^(3)-x^(2)-4x-1 and g(x)=x^(2)-3x-3 over the Interval [-1,2]the Region bounded by these curves over Interwal [-1,2] is shown in the graph by shaded parto then we have to find area of shaded part.for this first we finding intersection points of these carves rarr{:[x^(3)-x^(2)-4x-1=x^(2)-3x-3],[=>x^(3)-2x^(2)-x+2=0],[=>x=-1","2","1]:}function F(x)=x^(3)-x^(2)-4x-1 cuts x axls then{:[x^(3)-x^(2)-4x-1=0],[=>x=2.65","-0.27","-1.37]:}function g(x)=x^(2)-3x-3=0 cuts x axis then{:[x^(2)-3x-3=0],[=>x=3.79","-0.79]:}{:[" area "=[ ... See the full answer