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length of wire =30mlet the length and width, a and b respectivelyPerimeter of rectangle =2a+2b{:[2a+2b=30],[a+b=15],[" Area "=6(15**6)],[A=" Aura "=156-6^(2)]:}[a=15-6]diffecentiating it with mespect to 6{:[(dA)/(d theta)=15 xx1-26=0],[6=(15)/(2)quad a=(15)/(2)]:}Marimum Area is achieved only when the recraigh in a squain{:[" width "=" lugth "=15//2],[" Are ... See the full answer