QUESTION
Find the root of the following function using: a. Bisection Method b. Secant Method c. Newton's Method - $x-\sin (x)-(1 / 2)=0$, between the interval $(1,2)$ for tolerance: $<10^{-3}$ - $\mathrm{x}^{4}-\mathrm{x}-10=0$, between the interval $(1.5,2)$ for tolerance: $<10^{-3}$ d. Fixed Point Iteration - $X^{2}+2 x-15=0$, for initial value $x_{0}=2$ for tolerance $:<10^{-3}$
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