For each of the following complexes, give the hybrid orbital type and the number of
unpaired electrons.
(a) [Co(H2O)6]2+; (b) [FeCl6]3- (c) [PdCl4]2- (d) [Cr(H2O)6]2+
(a) [Co(H2O)6]2+Hybrid orbital type -sp^(3)d^(2)Number of unpaired electrons - 3(b) [FeCl6]3 -Hybrid orbital type -sp^(3)d^(2)Number of unpaired electrons - 5(c) [PdCl4]2-Hybrid orbital type -sp^(3)Number of unpaired electrons - 2(d) [Cr(H2O)6]2+Hybrid orbital type -sp^(3)d^(2)Number of unpaired electrons -Explanation:(a) [Co(H2O)6]2+Hybrid orbital type -s^(3)d^(2)Number of unpaired electrons - 3a) [CO_(O)H_(2)O_(6)]^(2+)[Ar]3d^(7)4s^(2)CO^(2+) ion [11//11//1//1//1(b) [FeCl6]3-Hybrid orbital type -s^(3)d^(2)Number of ... See the full answer