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{:[(d)/(dx)f(g(x))=(d)/(dg(x))f(g(x))xx(d)/(dx)(g(x))],[=f^(')(g(x))g^(')(x)],[:.(d)/(dx)(f(g(x)))∣],[x=2=f^(')(g(2))g^(')(2)],[=f^ ... See the full answer