Question Solved1 Answer Given two independent random samples with the following results: n1=16x‾1=162s1=21   n2=14x‾2=123s2=30 Use this data to find the 95% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval. Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3: Construct the 95%95% confidence interval. Round your answers to the nearest whole number.

WCCW3Z The Asker · Probability and Statistics

Given two independent random samples with the following results: n1=16x‾1=162s1=21   n2=14x‾2=123s2=30 Use this data to find the 95% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed.

Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval.

Step 2 of 3:

Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.

Step 3 of 3:

Construct the 95%95% confidence interval. Round your answers to the nearest whole number.

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ANSWER:-Given that{:[n_(1)=16,x_(1)=162,s_(1)=21],[n_(2)=14, bar(x_(2))=123,s_(2)=30]:}Confidence interval for true difference in roo population means when poubtion varances are not equal( bar(x)_(1)- bar(x)_(2))+-t_(d_(12),Delta)xxsqrt((s_(1)^(2))/(n_(1))+(s_(2)^(2))/(n_(2)))step-1 !{:[" point estimate "=( bar(x_(1))- bar(x_(2)))],[=162-123],[=39]:}Step -2Margin of error at 95%. confidence is,complete pooled variane and t-critical value find margin of error pookd variance is,{:[sp^(2)=((n_(1)-1)s_(1)^(2)+(n_(2)-1)s_(2)^(2))/((n-1)+(n_(2)-1))],[=((16-1)xx21 ... See the full answer