Fluid Mechanics

See Answer

Add Answer +20 Points

Community Answer

See all the answers with 1 Unlock

Get 4 Free Unlocks by registration

Get 4 Free Unlocks by registration

The detailed explanation of the derivation with assumptions is given below:-Q.Given data: -Initial velocity of puck is V_(0)puck is cuthioned by a thin air film of height h and viscosity mu as it travelsNow, Assumptions: -i) No other effects acting on the circular puck except the vicous force.ii) Velocity profile of air within the thin gop instantly adjusts itself to the instantaneous conditions of the peck.iii) Air followes Newton's law of viscosity. Let the velocity of the puck at some instant t is Vm//s.Now, By Newton's law of Escosity. Shear stress is directly broportional to the velocity gradient.{:[=>quad tau prop(dV)/(dh).],[=>quad tau=mu(dV)/(dh)quad{[" also assumed that "],[" The air film vis - "],[" cosity does not changu) "],[" with time "]:}],[=>quad tau=mu(V)/(h)quad{" By assumption (ui) "}". "]:}:. shear force due to viscosity isF_(mu)=mu(V)/(h)*A{ Where A is the area of puck in the contact with the air folm.:.A=(pi)/(4)D^(2)so, F_(mu)=mu(V)/(h)((pi)/(4)D^(2))=(1).Since, this force is acting is in the opposite direction of motion, :. it will froduce deacceleration in the motion of puck.Now ... See the full answer