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Sol4:- given that F_(1)=F_(2)=30lbrarr Components of F_(1) along x,y ax is areF_(1x)=F_(1)cos theta" and "F_(1y)=F_(1)sin thetararr Components of f_(2) along x,y a x is are-F_(2x)=F_(2)cos phi and F_(2y)=F_(2)sin phiwe know resultant force is only along tve x-axis and has magnitude of 40lb.{:[FR_(x)=F_(ix)+F_(2x)=30(cos theta+cos ph ... See the full answer