Question my answer is 0.036 w. but its incorrect In the circiut below calculate the total power dissipated in all the resistors. Use R1=240 2. R2=400 2, R3=460 2 V1=20 V, V2=23 V, and V3=20 V. 字 W. R1 R3 R2. w w V+ V34 V24
PHUDAJ The Asker · Electrical Engineering
my answer is 0.036 w. but its incorrect
Transcribed Image Text: In the circiut below calculate the total power dissipated in all the resistors. Use R1=240 2. R2=400 2, R3=460 2 V1=20 V, V2=23 V, and V3=20 V. 字 W. R1 R3 R2. w w V+ V34 V24
More Transcribed Image Text: In the circiut below calculate the total power dissipated in all the resistors. Use R1=240 2. R2=400 2, R3=460 2 V1=20 V, V2=23 V, and V3=20 V. 字 W. R1 R3 R2. w w V+ V34 V24
Community Answer
6RDBVR
Qui:- In the circuit below Calculate the total power dissipated in ale the resistors. USe R_(1)=240 Omega,R_(2)=400 Omega,R_(3)=460 Omega,V_(1)=20V,v_(2)=23V and v_(3)=20 vAnswer:-Apply KCL at Node A.{:[(V_(A)-V_(1))/(R_(1))+(V_(A-V_(3)))/(R_(3))+(V_(A-V_(2)))/(R_(2))=0],[(V_(A-20))/(240)+(V_(A)-20)/(460)+(V_(A)-23)/(400)=0]: ... See the full answer