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\$ .32\begin{array}{l}V_{x}=\frac{V_{b} .95 k}{100 k}=\frac{V_{0} .95}{100} \\\frac{V_{x}-V_{a}}{5 k}+\frac{V_{x}-V_{0}}{100 k}=0 \\100 v_{x}-100 v_{a}+5 v_{x}-5 v_{0}=0 \\105 v_{x}-100 v_{a}=\left(v_{0}\right) 5 \\v_{0}=21 v_{x}-20 v_{a} \\V_{0}=21\left(\frac{V_{b} .95}{100}\right)-20 V_{a} \Rightarrow V_{0}=19.95 V_{b}-20 V_{a}-\theta \\\end{array}(a) Ditferential mode gain A_{d}=-19.975(b) Common mode gain A_{c}=-0.05(c)\begin{array}{l}C M R R=\left|\frac{A_{\alpha}}{A_{c}}\right|=\left|\frac{-19.975}{0.05}\right|=399.5 \\C M R_{\alpha B}=20 \log \left|\frac{A_{\alpha}}{A_{C}}\right|=52.03 \mathrm{~dB}\end{array} ...