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Answer:- Given information pump speed of 820 rpm ud835udc58=130N/m Forcing frequency Wn 2N 60 27x820 60 Wn rad 85.87 sec ud835udc58=130N/m k .. Wn m 130 85.87 = m m = 0.0176 kg 21 - 800rpm T1 Ω1 N1 800 11 820 71 = 0.976 O2 = 840rpm Y2 Ω2 N1 12 840 820 T2 = 1.024 ri, r? = (1+) + u0f0d (1+g) + (1+ 2 – 1 for frac{w}{w_{n}}=1   Where u mi ** = (1+4) - 1 (1+5)*-1 1+ 5) -1=(1+)-u884c +1 -2- + 6+1)-1 - 6+1) + 2 2 +4+1= 2r} (1+2) +1 27 2 1+ 2 J = 2 ri+1 2r 2 (1+ri - 2 u = u = 1+(0.976) (0.976) 2 =0.00244 therefore m_{1}=frac{m}{mu } mi 0.0176 0.00244 mi 7.213 Kg Natural freq s ... See the full answer