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at x=-1a) f(-1)=-4quadlim_(x rarr-1^(-))f(x)=-4=lim_(x rarr-1^(+))f(x)f(x) is a Continuous at x=-1b) at x=1f(1) does not exestf(x) has discontinuous, but there is not enough information to tell which type.C) at x=2.5f(2.5)=3,lim_(x rarr2.5^(+))f(x)=-ooInfinite disc ... See the full answer