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LHS.\begin{aligned}P(A \cup B \cup C) & =1-P(\overline{A \cup B \cup C}) \\& =1-0.11 \\& =0.89\end{aligned}Now\begin{aligned}P(A) & =P(A \cap B)+P(A \cap C)+P(A \cap \bar{B} \cap \bar{C}) \\& =0.06+0.16+0.24 \\& =0.46\end{aligned}\begin{aligned}P(B) & =P(A \cap B)+P(B \cap C)+P(B \cap \bar{A} \cap \bar{C}) \\& =0.06+0.11+0.19=0.36 \\P(C) & =P(A \cap C)+P(C \cap B)+P(C \cap \bar{A} \cap \bar{B}) \\& =0.16+0.11+0.09 \\& =0.36\end{aligned}RHS\begin{array}{l}P(A)+P(B)+P(C)-P(A \cap B)-P(A \cap C)-P(B \cap C)+P[A \cap B \cap C) \\=0.46+0.36+0.36-0.06-0.16-0.11+0.04 \\=0.89 \\\text { LHS. = R.H.S } \\\end{array} ...