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Step1/1Answer can be solve in below imageSolution: -X is an exponential random variable with parameterlambdaChebyshev's Inequality for exponential random variable isP{|X-E(X)| >= ksigma_(x)} <= (1)/(k^(2))where k is a constantWe have to find outP{|X-E(X)| >= 2sigma_(x)}=" ? "Write down Chebyshev's Inequality here.Now Comparing above one with Chebyshe ... See the full answer