Question Let X1, X2,. . . , X100 denote the actual net weights of 100 randomly selected 50-lb bags of fertilizer. (Give answers accurate to 3 decimal places.) (a) If the expected weight of each bag is 50 and the variance of X is 1.3, calculate P(49.9 SX50.1) (approximately) using the CLT. (b) If the expected weight is 49.8 lb rather than 50 lb so that on average bags Let X1, X2,. . . , X100 denote the actual net weights of 100 randomly selected 50-lb bags of fertilizer. (Give answers accurate to 3 decimal places.) (a) If the expected weight of each bag is 50 and the variance of X is 1.3, calculate P(49.9 SX50.1) (approximately) using the CLT. (b) If the expected weight is 49.8 lb rather than 50 lb so that on average bags are underfilled, calculate P(49.9SXS 50.1)

FUDELN The Asker · Probability and Statistics

Transcribed Image Text: Let X1, X2,. . . , X100 denote the actual net weights of 100 randomly selected 50-lb bags of fertilizer. (Give answers accurate to 3 decimal places.) (a) If the expected weight of each bag is 50 and the variance of X is 1.3, calculate P(49.9 SX50.1) (approximately) using the CLT. (b) If the expected weight is 49.8 lb rather than 50 lb so that on average bags are underfilled, calculate P(49.9SXS 50.1)
More
Transcribed Image Text: Let X1, X2,. . . , X100 denote the actual net weights of 100 randomly selected 50-lb bags of fertilizer. (Give answers accurate to 3 decimal places.) (a) If the expected weight of each bag is 50 and the variance of X is 1.3, calculate P(49.9 SX50.1) (approximately) using the CLT. (b) If the expected weight is 49.8 lb rather than 50 lb so that on average bags are underfilled, calculate P(49.9SXS 50.1)
Community Answer
AL3UMC

Answer:-(a){:[P(49.9 <= bar(x) <= 50.1)],[=P((49.9-50)/(sqrt((1.3)/(100))) <= (( bar(x))-" mean ")/(sqrt((5)/(100))) <= (50.1-50)/(sqrt((1.3)/(100))))],[=P(-0.87 <= 2 <= 0.87)],[=0.8106-0.1897],[=0.62 ... See the full answer

VZIBCY

Answer:-(a){:[P(49.9 <= bar(x) <= 50.1)],[=P((49.9-50)/(sqrt((1.3)/(100))) <= (( bar(x))-" mean ")/(sqrt((5)/(100))) <= (50.1-50)/(sqrt((1.3)/(100))))],[=P(-0.87 <= 2 <= 0.87)],[=0.8106-0.1897],[=0.62 ... See the full answer