Let *Y* denote a random variable that has a
Poisson distribution with mean *λ* = 6.
(Round your answers to three decimal places.)

(a) Find * P*(

(b) Find * P*(

(c) Find * P*(

(d) Find * P*(

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 Y denotes a random variable that has a Poisson distribution with mean λ = 6 The probability of Y=y is P(Y=y)=(lambda^(y)e^(-lambda))/(y!)=(6^(y)e^(-6))/(y!),quad y=0,1,dots (a) Find P(Y = 9). P(Y=9)=(6^(9)e^(-6))/(9!)=0.0688 ans: P(Y=9) = 0.069 (b) Find P(Y ≥ 9). {:[P(Y >= 9)=1-P(Y < 9)],[=1-(P(Y=0)+P(Y=1)+dots+P(Y=8))],[=1-((6^(0)e^(-6))/(0!)+(6^(1)e^(-6))/(1!)+dots+(6^(8)e^(-6))/(8!))],[=1-(0.0025+0.0149+0.0446+0.0892+0.1339+0.1606+0.1606+0.1377+0.1033)],[=0.1528]:} ans: P(Y ≥ 9) = 0.153 (c) Find P(Y < 9) {:[P(Y < 9)=1-P(Y >= 9)],[=1-0.1528" from part "b],[=0. ... See the full answer