Question Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Round all answers to two decimal places.) (a) P(Z < z*) = 0.025 z* = (b) P(Z < z*) = 0.0098 z* (C) P(Z < z*) = 0.0506 z* = (d) P(Z > z*) = 0.0195 z* = (e) P(Z > z*) = 0.0098 z* = (f) P(Z > z* or z < -z*) = 0.2038 Z* =
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Transcribed Image Text: Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Round all answers to two decimal places.) (a) P(Z < z*) = 0.025 z* = (b) P(Z < z*) = 0.0098 z* (C) P(Z < z*) = 0.0506 z* = (d) P(Z > z*) = 0.0195 z* = (e) P(Z > z*) = 0.0098 z* = (f) P(Z > z* or z < -z*) = 0.2038 Z* =
More Transcribed Image Text: Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Round all answers to two decimal places.) (a) P(Z < z*) = 0.025 z* = (b) P(Z < z*) = 0.0098 z* (C) P(Z < z*) = 0.0506 z* = (d) P(Z > z*) = 0.0195 z* = (e) P(Z > z*) = 0.0098 z* = (f) P(Z > z* or z < -z*) = 0.2038 Z* =
Community Answer
NE2FFF
If z∼N(0,1) then" cod.f. "F(z)=P(z <= z^(**))A standard normal table gives the less thon equal to probabilities.a) p(z < z^(***))=0.025. From a standard normal tablep(7 < -1.96)~~0.025=>z^(**)=-1.96b) p(z < z^(**))=0,0098But, P(z < -2.33)~~0.0098=>z^(**)=-2.33{:[" c) "P(z < z^(**))=0.0506],[:'P*(z < -1.64)~~0.0506=>z^(**)=-1.64]:}{:[" d) "P(z > z^(**))=0.0195],[=>1-P(z < z^(**))=0.9805],[=>P(z < ... See the full answer