Question Let \( z \) denote a variable that has a standard normal distribution. Determine the value \( z^{*} \) to satisfy the following conditions. (Round your answers to two decimal places.) (a) \( P\left(z<z^{*}\right)=0.0256 \) \[ z^{*}= \] (b) \( P\left(z<z^{*}\right)=0.0101 \) \[ z^{*}= \] (c) \( P\left(z<z^{*}\right)=0,0502 \) \[ z^{*}= \] (d) \( Let z denote a variable that has a standard normal distribution. Determine the value z∗ to satisfy the following conditions. (Round your answers to two decimal places.) (a) P(z<z∗)=0.0256 z∗= (b) P(z<z∗)=0.0101 z∗= (c) P(z<z∗)=0,0502 z∗= (d) P(z>z∗)=0.0206 z∗= (e) P(z>z∗)=0.0101 z∗= (f) P(z>2∗ or z<−2∗)=0.2044 z∗= f(x)

JRUO1I The Asker · Probability and Statistics

Transcribed Image Text: Let z denote a variable that has a standard normal distribution. Determine the value z∗ to satisfy the following conditions. (Round your answers to two decimal places.) (a) P(zz∗)=0.0206 z∗= (e) P(z>z∗)=0.0101 z∗= (f) P(z>2∗ or z<−2∗)=0.2044 z∗= f(x)
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Transcribed Image Text: Let z denote a variable that has a standard normal distribution. Determine the value z∗ to satisfy the following conditions. (Round your answers to two decimal places.) (a) P(zz∗)=0.0206 z∗= (e) P(z>z∗)=0.0101 z∗= (f) P(z>2∗ or z<−2∗)=0.2044 z∗= f(x)
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9RAEXV

Sol:(a) p(z < z**)=0.02562^(**)=-1.95 rarr from standeard normal z-table values (left-xil test)(b)d normal z-tble values (lett-tail test)(c) p(z < z^(**))=0,0502z^(**)=-1.64(d) p(z > 2^(**))=0.0206z^(**)=2.04 rarr from staddeud normal z-t ... See the full answer