Sol:(a) p(z < z**)=0.02562^(**)=-1.95 rarr from standeard normal z-table values (left-xil test)(b)d normal z-tble values (lett-tail test)(c) p(z < z^(**))=0,0502z^(**)=-1.64(d) p(z > 2^(**))=0.0206z^(**)=2.04 rarr from staddeud normal z-t ... See the full answer