Question Solved1 Answer Liquid carbon tetrachloride is pumped from a large storage tank through a 2.25-inch ID pipe at a rate of 1.25 L/min. At what rate in ft·lbf/s and hp is kinetic energy being transported by the carbon tetrachloride in the pipe? EK - ON x 10-3 ft·lbf/s or i x 10-6 hp

9. The ester of an organic base hydrolyzed in a CSTR. The rate of this irre- versible reaction is first-order in each reactant. The liquid volume in the vessel is 6500 L. A jacket with coolant at 18°C maintains the reactant mixture at 30°C. Additional data: Ester feed stream–1 M, 30°C, 20 L/s Base feed stream-4 M, 30°C, 10 L/s Rate constant = 10'4 exp(-11,000/T) M-'s-1, T in K AH, = -45 kcal/mol ester The average heat capacity is approximately constant at 1.0 kcal L-lºc-. (a) What is the conversion of ester in the reactor? (b) Calculate the rate at which energy must be removed to the jacket to maintain 30°C in the reactor. If the heat transfer coefficient is 15 kcal s-'m-2 K-, what is the necessary heat transfer area? (c) If the coolant supply fails, what would be the maximum temperature the reactor could reach? ir carried out in an adiabatic CSTR with a volume of 10,000 L. SM is supplied at 10

The effect of temperature on the rate of a reaction was studied and the following data obtained: k (5-1) T(°C) 1.63X10-4 6 1.92 x 10-4 8 2.86X10-4 13 3.89 x 10-4 17 5.65x10-4 22 1.00X10-3 30 1.15x10-3 32 1.41 x 10-3 35 It is known that the variation of the rate constant k with the absolute temperature T is described by the Arrhenius equation: k = A exp [(-E, (RT)] where Ez is the activation energy, R is the universal gas constant and A is the pre-exponential factor (units of the rate constant). Taking the natural logarithm of both sides affords: E In k = In A - RT For a plot of y = In k versus x = 1/T, calculate the slope of the best straight line using linear regression. 1 pts Submit Answer Tries 0/99 Calculate the activation energy Ea. 1 pts

"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters \( (R, G, B, Y \) ) and the user must repeat the sequence, Create a for loop that compares the two strings starting from index 0 . For each match, add one point to userScore Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R,G,B,Y ) and the user must repeat the sequence, Create a for loop that compares the two strings starting from index 0 . For each match, add one point to userScore Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex The following patterns yield a userScore of 4 : simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY 3 public class SimonSays \{ 4 public static void main (String □ args) \{ 5 Scanner scnr = new Scanner(System, in) 6 String simonPattern; 7 String userPattern; 8 int userscore; int i; user 5 core =0; simonPattern = scnr. next ); userPattern = scnr, next O; System. out.println("userScore: "+ userScore);

"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length.Ex: The following patterns yield a userScore of 4:simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY import java.util.Scanner;public class SimonSays {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);String simonPattern;String userPattern;int userScore;int i;userScore = 0;simonPattern = scnr.next();userPattern = scnr.next();/* Your solution goes here */System.out.println("userScore: " + userScore);return;}} 

"Simon Says"simonPattern: RRGBRYYBGYuserPatteen: RRGBBRYBGY "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex: The following patterns yield a userScore of 4: simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY 1 import java.util.Scanner; 2 3 public class SimonSays { 4 public static void main(String[] args) { 5 7 9 10 11 12 13 14 15 Scanner scnr- new Scanner(System.in); String simonPattern; String userPattern; int userScore; int i; userScore - 0; simonPattern scnr.next(); userPattern = scnr.next(): DID!! p d

Air at 80 degrees Fahrenheit and 14.7 psia with a mass flow rate of 0.6 lbm/sec enters a compressor and leaves at 70 psia and 430 degrees Fahrenheit through an exit area of 0.007 ft^2.  The measured heat interaction rate with the 80 degree Fahrenheit factory room is 3 Btu/sec.  Use constant Cp = 0.24 Btu/lbm oF a) Calculate the compressor work rate.   b) Compute the entropy generation rate for the overall process.