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N_(2) & N_(3) are the normal forces on belock 2&3 f_(2)&f_(3) are the frictional forcesThe acceleration a=2.35m//s^(2) to the left Consider m ass m,m_(1)g-T_(1)=m_(1)a-" (1) "Consider mass m_(2){:[m_(2)g=N_(2)quadf_(2)=muN_(2)=Mm_(2)g],[:.T_(1)-T_(2)-f_(2)=m_(2)a],[T_(1)-T_(2)=Mm_(2)g=m_(2)a-" (2) "],[N_(3)=m_(3)g cos thetaquadf_(3)=muN_(3)],[=mu mg cos theta],[T_(2)-f_(3)-m_(3) ... See the full answer