Question Solved1 Answer m2 592 The three blocks shown (10.0 kg, 5.0 kg, and 3.0 kg. respectively) are connected by massless strings that pass over frictionless pulleys. The acceleration of the system is 2.35 m/s to the left and the surfaces are rough. Find a) the tensions in the strings and b) the coefficient of kinetic friction between blocks and surfaces (assume u is same for both blocks) ms 3.0 kg mi 10 kg 0=25

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Transcribed Image Text: m2 592 The three blocks shown (10.0 kg, 5.0 kg, and 3.0 kg. respectively) are connected by massless strings that pass over frictionless pulleys. The acceleration of the system is 2.35 m/s to the left and the surfaces are rough. Find a) the tensions in the strings and b) the coefficient of kinetic friction between blocks and surfaces (assume u is same for both blocks) ms 3.0 kg mi 10 kg 0=25
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Transcribed Image Text: m2 592 The three blocks shown (10.0 kg, 5.0 kg, and 3.0 kg. respectively) are connected by massless strings that pass over frictionless pulleys. The acceleration of the system is 2.35 m/s to the left and the surfaces are rough. Find a) the tensions in the strings and b) the coefficient of kinetic friction between blocks and surfaces (assume u is same for both blocks) ms 3.0 kg mi 10 kg 0=25
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N_(2) & N_(3) are the normal forces on belock 2&3 f_(2)&f_(3) are the frictional forcesThe acceleration a=2.35m//s^(2) to the left Consider m ass m,m_(1)g-T_(1)=m_(1)a-" (1) "Consider mass m_(2){:[m_(2)g=N_(2)quadf_(2)=muN_(2)=Mm_(2)g],[:.T_(1)-T_(2)-f_(2)=m_(2)a],[T_(1)-T_(2)=Mm_(2)g=m_(2)a-" (2) "],[N_(3)=m_(3)g cos thetaquadf_(3)=muN_(3)],[=mu mg cos theta],[T_(2)-f_(3)-m_(3) ... See the full answer