Solved 1 Answer
See More Answers for FREE
Enhance your learning with StudyX
Receive support from our dedicated community users and experts
See up to 20 answers per week for free
Experience reliable customer service
Step 1Given,H→x,y;t=e→z 2 sinπ23x+4y-3108t A/ma.  Amplitude = 2 A/mFrequency=ω=3π2×108 f=34×108= 75 MHzβ=π232+42=5π2β=5π2⇒2πλ=5π2λ=45=0.8 mProagation direction=a^p=3a^x+4a^y5b. vp=ωβ=3π2×1085π2=35×108vp=cμrεr=2εr=3×10835×1082εr=25εr=12.5Step 2c. Direction of electric fielda^E=a^xa^p=-ax×153a^x+4a^y=-45azη=120πμrεr=120π212.5=150.79E→=ηH→=-e→z 2 ×150.79×sin3π2 ×108t-π23x+4y A/md. phasorE→=-241.264e^ze-πj23x+4yVme.H→=-2e^xe-πj23x+4yAm   ...