Home / Engineering & CS / Mechanical Engineering /Moist air at 1 atmosphere and 30°C has a relative humidity of 50%. What is the humidity ratio (w) of the air? 0.0212 0.0425 O 0.0136 0.50 Liquid water is injected into a sealed, thermally insulated container of dry air, so that it collects at the base. It is observed, over time, to completely evaporate, with the moist air now at a slightly cooler temperature. Which of the following is the correct explanation. Heat generated by the evaporation process drives further evaporation. So ALL of the water must eventually evaporate. In a sealed container the water could not have possibly evaporated. There must either be heat input into the container from an external source, or a leak in the container allowing vapour to escape. This cannot happen. At equilibrium, condensation and evaporation occur at equal rates, so some water will always remain. The water will tend find its equilibrium as a liquid/vapour mix at a saturated temperature/pressure combination. However, if there is insufficient liquid water for the vapour's partial pressure to reach its saturation value, it will completely evaporate. And evaporative cooling occurs as a consequence. If a psychrometric mixture at 1 bar is comprised of water/air mixture where the mass ratio of water to air is 1%, what is the partial pressure of the air? O 0.947 bar 0.995 bar 0.972 bar 0.984 bar Which of the follow statements best describes the Dalton model for moist air? Moist air is dry air that contains small "atomised" droplets of liquid water, all at a common temperature. Dry air and water vapour coexist as ideal gases - sharing common volume and temperature, but contributing partial pressures. Moist air may be considered as a saturated liquid-vapour mix of water, as the energy density of the water component is far greater than the air. Dry air and water vapour coexist as ideal gases - sharing common pressure and temperature, but contributing partial volumes. Exhaust from a car may be very crudely modeled as a water/air ideal gas mixture at 1 atmosphere pressure. If exhaust vapour condenses at 55°C, what is its humidity ratio (w)? O 0.1576 0.1146 0.3230 The question does not make sense. Car exhaust is an ideal gas, and so does not condense.

Question Moist air at 1 atmosphere and 30°C has a relative humidity of 50%. What is the humidity ratio (w) of the air? 0.0212 0.0425 O 0.0136 0.50 Liquid water is injected into a sealed, thermally insulated container of dry air, so that it collects at the base. It is observed, over time, to completely evaporate, with the moist air now at a slightly cooler temperature. Which of the following is the correct explanation. Heat generated by the evaporation process drives further evaporation. So ALL of the water must eventually evaporate. In a sealed container the water could not have possibly evaporated. There must either be heat input into the container from an external source, or a leak in the container allowing vapour to escape. This cannot happen. At equilibrium, condensation and evaporation occur at equal rates, so some water will always remain. The water will tend find its equilibrium as a liquid/vapour mix at a saturated temperature/pressure combination. However, if there is insufficient liquid water for the vapour's partial pressure to reach its saturation value, it will completely evaporate. And evaporative cooling occurs as a consequence. If a psychrometric mixture at 1 bar is comprised of water/air mixture where the mass ratio of water to air is 1%, what is the partial pressure of the air? O 0.947 bar 0.995 bar 0.972 bar 0.984 bar Which of the follow statements best describes the Dalton model for moist air? Moist air is dry air that contains small "atomised" droplets of liquid water, all at a common temperature. Dry air and water vapour coexist as ideal gases - sharing common volume and temperature, but contributing partial pressures. Moist air may be considered as a saturated liquid-vapour mix of water, as the energy density of the water component is far greater than the air. Dry air and water vapour coexist as ideal gases - sharing common pressure and temperature, but contributing partial volumes. Exhaust from a car may be very crudely modeled as a water/air ideal gas mixture at 1 atmosphere pressure. If exhaust vapour condenses at 55°C, what is its humidity ratio (w)? O 0.1576 0.1146 0.3230 The question does not make sense. Car exhaust is an ideal gas, and so does not condense.

I9RTRC The Asker · Mechanical Engineering

Transcribed Image Text: Moist air at 1 atmosphere and 30°C has a relative humidity of 50%. What is the humidity ratio (w) of the air? 0.0212 0.0425 O 0.0136 0.50 Liquid water is injected into a sealed, thermally insulated container of dry air, so that it collects at the base. It is observed, over time, to completely evaporate, with the moist air now at a slightly cooler temperature. Which of the following is the correct explanation. Heat generated by the evaporation process drives further evaporation. So ALL of the water must eventually evaporate. In a sealed container the water could not have possibly evaporated. There must either be heat input into the container from an external source, or a leak in the container allowing vapour to escape. This cannot happen. At equilibrium, condensation and evaporation occur at equal rates, so some water will always remain. The water will tend find its equilibrium as a liquid/vapour mix at a saturated temperature/pressure combination. However, if there is insufficient liquid water for the vapour's partial pressure to reach its saturation value, it will completely evaporate. And evaporative cooling occurs as a consequence. If a psychrometric mixture at 1 bar is comprised of water/air mixture where the mass ratio of water to air is 1%, what is the partial pressure of the air? O 0.947 bar 0.995 bar 0.972 bar 0.984 bar Which of the follow statements best describes the Dalton model for moist air? Moist air is dry air that contains small "atomised" droplets of liquid water, all at a common temperature. Dry air and water vapour coexist as ideal gases - sharing common volume and temperature, but contributing partial pressures. Moist air may be considered as a saturated liquid-vapour mix of water, as the energy density of the water component is far greater than the air. Dry air and water vapour coexist as ideal gases - sharing common pressure and temperature, but contributing partial volumes. Exhaust from a car may be very crudely modeled as a water/air ideal gas mixture at 1 atmosphere pressure. If exhaust vapour condenses at 55°C, what is its humidity ratio (w)? O 0.1576 0.1146 0.3230 The question does not make sense. Car exhaust is an ideal gas, and so does not condense.
More
Transcribed Image Text: Moist air at 1 atmosphere and 30°C has a relative humidity of 50%. What is the humidity ratio (w) of the air? 0.0212 0.0425 O 0.0136 0.50 Liquid water is injected into a sealed, thermally insulated container of dry air, so that it collects at the base. It is observed, over time, to completely evaporate, with the moist air now at a slightly cooler temperature. Which of the following is the correct explanation. Heat generated by the evaporation process drives further evaporation. So ALL of the water must eventually evaporate. In a sealed container the water could not have possibly evaporated. There must either be heat input into the container from an external source, or a leak in the container allowing vapour to escape. This cannot happen. At equilibrium, condensation and evaporation occur at equal rates, so some water will always remain. The water will tend find its equilibrium as a liquid/vapour mix at a saturated temperature/pressure combination. However, if there is insufficient liquid water for the vapour's partial pressure to reach its saturation value, it will completely evaporate. And evaporative cooling occurs as a consequence. If a psychrometric mixture at 1 bar is comprised of water/air mixture where the mass ratio of water to air is 1%, what is the partial pressure of the air? O 0.947 bar 0.995 bar 0.972 bar 0.984 bar Which of the follow statements best describes the Dalton model for moist air? Moist air is dry air that contains small "atomised" droplets of liquid water, all at a common temperature. Dry air and water vapour coexist as ideal gases - sharing common volume and temperature, but contributing partial pressures. Moist air may be considered as a saturated liquid-vapour mix of water, as the energy density of the water component is far greater than the air. Dry air and water vapour coexist as ideal gases - sharing common pressure and temperature, but contributing partial volumes. Exhaust from a car may be very crudely modeled as a water/air ideal gas mixture at 1 atmosphere pressure. If exhaust vapour condenses at 55°C, what is its humidity ratio (w)? O 0.1576 0.1146 0.3230 The question does not make sense. Car exhaust is an ideal gas, and so does not condense.

Related Questions

Determine the x-and y-coordinates of the centroid of the shaded area. Assume c = 6, a = 1.10, b = 1.90. = y 1 1 1 x 3 y=1+ © с ob- --X a b Answer: (1,5) = ( Locate the centroid of the shaded area. Set b= 0.40 a. y | *=a(1-1 y2 62 b * a Answer: (Ă, y) = ( Determine the x-and y-coordinates of the centroid of the shaded area. у | a | y = k2v x 1.20 a y = k123 Answers: (1. y) =(
Biostatistics ESSAY A firm investigates the length of telephone conversations of their office staff. Ten consecutive conversations had lengths, in minutes: 10.7, 9.5, 11.1, 7.8, 11.9, 4.1, 10.0, 9.2, 6.5, 9.2. Derive a 95% confidence interval for the mean conversation length. Test whether the mean length of a conversation is eight minutes.(25 MARKS)
A cylindrical rock sample has a length of 6 cm, a diameter of 4 cm, and a dry weight of 166.4 g. When fully saturated with an oil of density 0.85 g/cm3, the weight of this sample is 176.9 g. Assuming constant temperature, find: i) The porosity of the sample ii) The pore compressibility of the sample, given that 0.2 cm of oil leaves the sample when a pressure of 3200 psig is applied on it iii) The amount of oil that can be extracted from the sample when a pressure of 2000 psig is applied on it
2.7 LAB - Alter Movie table The Movie table has the following columns: ID - integer, primary key Title - variable-length string Genre - variable-length string RatingCode - variable-length string Year - integer Write ALTER statements to make the following modifications to the Movie table: Add a Producer column with VARCHAR data type (max 50 chars). Remove the Genre column. Change the Year column's name to ReleaseYear, and change the data type to SMALLINT.
Victory Company uses weighted average process costing. The company has two production processes. Conversion cost is added evenly throughout each process. Direct materials are added at the beginning of the first process Additional information for the first process follows Direct Materials Conversion Percent Percent Units Complete Complete Beginning work in process inventory 72, eee 100% 80% Units started this period 833,eee Units completed and transferred out 71e,eee Ending work in process inventory 195, eee 1ees 50% Beginning work in process inventory Direct materials $ 411,775 Conversion 100,938 $ 512, 713 Costs added this period Direct materials 2,755,725 Conversion 1,917,812 4,673,537 Total costs to account for $ 5,186,250 Required: 1. Compute equivalent units of production for both direct materials and conversion Equivalent Units of Production (EUP). Weighted Average Method Units % Materials EUP-Materials % Conversion EUP. Conversion Total units 2. Compute cost per equivalent unit of production for both direct materials and conversion Cost per equivalent unit of production Materials Conversion Costs Costs Total costs Equivalent units of production (from part 1) Cost per equivalent unit of production EUP EUP 0 0 3. Assign costs to the department's output-specifically, to the units transferred out and to the units in ending work in process Inventory (Round "Cost per EUP" to 2 decimal places.) EUP Cost per EUP Total cost Cost assignment-Weighted average Completed and transferred out Direct materials Conversion Total completed and transferred out Ending work in process Direct materials Conversion Total ending work in process Total costs accounted for $ 0 0.00 $ 0.00 S 0
Help in SQL.. please take your time 3.12 LAB - Create LessonSchedule table with FK constraints Two tables are created: 1. Horse with columns: - ID - integer, primary key RegisteredName - variable-length string 2. Student with columns: ID - integer, primary key FirstName - variable-length string LastName - variable-length string Create the Lesson Schedule table with columns: • HorselD-integer with range 0 to 65 thousand, not NULL, partial primary key, foreign key references HorseID) • StudentID - integer with range 0 to 65 thousand, foreign key references Student(ID) • LessonDate Time - date/time, not NULL, partial primary key If a row is deleted from Horse, the rows with the same horse ID should be deleted from LessonSchedule automatically. If a row is deleted from Student, the same student IDs should be set to NULL in Lesson Schedule automatically. 387240.1399152.qx3zay? LAB ACTIVITY 3.12.1: LAB - Create Lesson Schedule table with FK constraints 0/10 Main.sql Load default template... 1 CREATE TABLE Horse ( 2 ID SMALLINT UNSIGNED AUTO_INCREMENT, 3 RegisteredName VARCHAR(15), 4. PRIMARY KEY (ID) 5); 7 CREATE TABLE Student ( 8 ID SMALLINT UNSIGNED AUTO_INCREMENT, 9 FirstName VARCHAR(20), 10 LastName VARCHAR(30), 11 PRIMARY KEY (ID) 12 ); 13 If a row is deleted from Student, the same student IDs should be set to NULL in LessonSchedule automatically. SB/270.7399152 gy LAB ACTIVITY 3.12.1: LAB - Create Lesson Schedule table with FK constraints 0/10 Main.sql Load default template... 1 CREATE TABLE Horse 2 2 ID SMALLINT UNSIGNED AUTO_INCREMENT, 3 RegisteredName VARCHAR(15), 4 PRIMARY KEY (ID) 5); 6 7 CREATE TABLE Student 8 ID SMALLINT UNSIGNED AUTO_INCREMENT, 9 FirstName VARCHAR(20), 10 Last Name VARCHAR(30), 11 PRIMARY KEY (ID 12); 13 14 -- Your SQL statements go here 15 16 17 Develop mode Submit mode Explore the database and run your program as often as you'd like, before submitting for grading. Click Run program and observe the program's output in the second box. Main.sql Run program Output (shown below) (Your program) Program output displayed here Coding trail of your work What is this? History of your effort will appear here once you begin working on this zylab.
About
About
Blog
Sitemap
More
Help Center
Become an Expert
Download App
Legal
Terms of Service
Privacy Policy
Honor Code
Copyright Policy
Contact
contact@studyx.im
Facebook
Instagram
Twitter
YouTube
Copyright © 2023 StudyX Inc