Question NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part A ballistic pendulum is used to measure the speed of high-speed projectiles. A bullet A weighing 22 g is fired into a 25 kg wood block B suspended by a cord of length 122 m. The block then swings through a maximum angle of 860 O В Determine the initial speed of the bullet vo. The initial speed of the bulletis m/s

Given,weight of buelet =22 gram =M_{b}Mass of wood block =1.6 \mathrm{~kg}=M_{B}Length of cord, l=2.2 \mathrm{~m}Maximum angle swings by block, \theta=60^{\circ}Initial condition, \theta=0Initially, P \cdot E=0K \cdot E=\frac{1}{2} M V^{2}Initial positionWhere, M= mass of bulet + Mass of blockv= relocity intially of systemFinal condition, \theta=60^{\circ}k \cdot E=0Apply conservation of energyTotal initial Energy = Total final energy\begin{array}{l} 0+\frac{1}{2} M v^{2}=M g(l-l \cos 60)+0 \\v=\sqrt{2 g l(1-\cos 60)} \\v=\sqrt{2 \times 9.81 \times 2.2 \times 0.5}=4.6456 \mathrm{~m} / \mathrm{s} \\V=4.6456 \mathrm{~m} / \mathrm{s} \rightarrow \text { velocity of system }\end{array}Apply the conserration of momentum principle for the bullet and block before and after hitting the blockM_{b} v_{0}+M_{B} v_{1}=M vWhere, M= Mass of systemV_{0}= initial velocity of bulletv_{1}= initial velociey of blockV= velocity of systemInitially block is at rest \Rightarrow V_{1}=0\begin{array}{c}\frac{22}{1000} \times V_{0}+1.6 \times 0=1.622 \times 4.6456 \\N_{0}=342.51 \mathrm{~m} / \mathrm{s}\end{array}\rightarrow initial recocity of bullet The detailed solution of this question is uploaded.ig you have any doubt or confusion in my solution then please mention in the comment section... Give me positive rating...ud83dude4fud83dude4fud83dude4f Thank You...ud83dude0aud83dude0aud83dude0a ...