Question Solved1 Answer One pathway for the destruction of ozone in the upper atmosphere is O3(g) + NO(g) -> NO2(g) + O2(g) Slow NO2(g) + O(g) -> NO(g) + O2(g) Fast Overall reaction: O3(g) + O(g) -> 2O2(g) Identify the correct term to describe each of the following species. Catalyst: nitrogen monoxide Product: molecular (di)oxygen Intermediate: NO2(g) Reactant: O3(g) Reactant: O(g) 1 pts You are correct. Previous Tries Ea is 14.0 kJ/mol, for the uncatalyzed reaction: O3(g) + O(g) -> 2O2(g) Ea for the same reaction, when catalyzed as above, is 11.9 kJ/mol. At -44°C, what is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction? (Assume the frequency factor A is the same for each reaction.) 1 pts Tries 0/5 One of the concerns about the use of freons is that they will migrate to the upper atmosphere, where chlorine atoms can be generated by the reaction CCl2F2 -> CF2Cl + Cl (photolysis of Freon-12) Chlorine atoms can also act as a catalyst for the destruction of ozone. The activation energy for the reaction Cl + O3 -> ClO + O2 is 2.1 kJ/mol. Cl is regenerated by the fast reaction ClO + O -> O2 + Cl If the frequency factors are the same and both catalysts are in equal concentration, how many times faster, at -52°C, does the Cl catalysed reaction proceed compared to the reaction catalysed as described in the previous question.

7OTDDX The Asker · Chemistry

One pathway for the destruction of ozone in the upper atmosphere is

O3(g) + NO(g) -> NO2(g) + O2(g) Slow
NO2(g) + O(g) -> NO(g) + O2(g) Fast
Overall reaction: O3(g) + O(g) -> 2O2(g)

Identify the correct term to describe each of the following species.
Catalyst: nitrogen monoxide
Product: molecular (di)oxygen
Intermediate: NO2(g)
Reactant: O3(g)
Reactant: O(g)

1 pts

You are correct. Previous Tries

Ea is 14.0 kJ/mol, for the uncatalyzed reaction:

O3(g) + O(g) -> 2O2(g)

Ea for the same reaction, when catalyzed as above, is 11.9 kJ/mol.
At -44°C, what is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction?
(Assume the frequency factor A is the same for each reaction.)

1 pts

Tries 0/5

One of the concerns about the use of freons is that they will migrate to the upper atmosphere, where chlorine atoms can be generated by the reaction

CCl2F2 -> CF2Cl + Cl (photolysis of Freon-12)

Chlorine atoms can also act as a catalyst for the destruction of ozone.
The activation energy for the reaction

Cl + O3 -> ClO + O2

is 2.1 kJ/mol.

Cl is regenerated by the fast reaction

ClO + O -> O2 + Cl

If the frequency factors are the same and both catalysts are in equal concentration, how many times faster, at -52°C, does the Cl catalysed reaction proceed compared to the reaction catalysed as described in the previous question.

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For No catalyzedK_(N0)=Ae^(-(11.9 xx10^(3))/(RT))for al cataly zedK_(al)=Ae^(-(2*1xx10^(3))/(RT))A is same for both reaction{:[T rarr-52^(@)C=273-52=221K],[=e^(((9.8 xx10^(3))/(8.314 xx21)))],[=207.19],[(Kal_(KNO))/()=207.2]:}(2)Since frequency factor is same for catalyzed and uncatalyzed reaction therefore ratio of rate constant will depend only on activation energy and Temperature. for details solution please refer Image   Calculation of ratio of rate constant of catalyzed to ... See the full answer