Question P5.039 A load P is supported by a structure consisting of rigid bar BDF and three identical 20-mm-diameter steel [E = 200 GPa] rods, as shown in the figure. Use a = 1.7 m, b = 1.0 m, and L = 2.1 m. For a load of P = 79 kN, determine (a) the tension force produced in each rod. (b) the downward vertical deflection of the rigid bar at B. P5.039 A load P is supported by a structure consisting of rigid bar BDF and three identical 20-mm-diameter steel [E = 200 GPa) rods, as shown in the figure. Use a = 1.7 m, b = 1.0 m, and L = 2.1 m. For a load of P = 79 kN, determine (a) the tension force produced in each rod. (b) the downward vertical deflection of the rigid bar at B. Answers: (a) F1 = F2= (b) vb =

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P5.039

A load P is supported by a structure consisting of rigid bar BDF and three identical 20-mm-diameter steel [E = 200 GPa] rods, as shown in the figure. Use a = 1.7 m, b = 1.0 m, and L = 2.1 m. For a load of P = 79 kN, determine

(a) the tension force produced in each rod.
(b) the downward vertical deflection of the rigid bar at B.

Transcribed Image Text: P5.039 A load P is supported by a structure consisting of rigid bar BDF and three identical 20-mm-diameter steel [E = 200 GPa) rods, as shown in the figure. Use a = 1.7 m, b = 1.0 m, and L = 2.1 m. For a load of P = 79 kN, determine (a) the tension force produced in each rod. (b) the downward vertical deflection of the rigid bar at B. Answers: (a) F1 = F2= (b) vb =
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Transcribed Image Text: P5.039 A load P is supported by a structure consisting of rigid bar BDF and three identical 20-mm-diameter steel [E = 200 GPa) rods, as shown in the figure. Use a = 1.7 m, b = 1.0 m, and L = 2.1 m. For a load of P = 79 kN, determine (a) the tension force produced in each rod. (b) the downward vertical deflection of the rigid bar at B. Answers: (a) F1 = F2= (b) vb =
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{:[P=79kN],[E=200GPa]:}drameter of each rodd=20mmcross sectional AreaA=(pi)/(4)d^(2)=(pi)/(4)xx(20)^(2)mm^(2)F_(1)= force in rod (1)F_(2)= force in rod 2F_(3)= force in rod (3)take moment at F=0{:[F_(1)xx3.4+F_(2)xx1.7-79 xx2.4=0],[3.4F_(1)+1.7F_(2)=79 xx2.4],[SigmaF_(y)=0quadF_(1)+F_(2)+F_(3)=79]:}change in length of Rod ( D= displacement at point (B)delta_(1)=delta_(B)=(F_(1)L)/(AE)=(F_(1)xx2100)/((pi)/(4)xx20^(2)xx200)chonge en length of Rod 2 = displacement at pout(D)delta_(2)=delta_(D)=(F_(2)L)/(AE)=(F_(2)xx2100)/((pi)/(4)xx20^(2)xx200)change in length of Rod(3)= displacement of point (F)delta_(3)=delta_(F)=(F_(3)L)/(A ... See the full answer